The idea is that if the direction is east, and a baboon wants to travel west, the block_east interrupt can be set to block any additional baboons on the east side.  

east = semaphore(1);    // east side control
west = semaphore(1);    // west side control
mutex = semaphore(1);   // provide mutual exclusion for four variables
rope = semaphore(5);    // ensure only 5 baboons are on the rope at a time

count = 0;      // number of baboons granted access to the rope
block_east = 0  // interrupt for east side to block itself
block_west = 0  // interrupt for west side to block itself
wait_west = 0   // queue count for west side
wait_east = 0   // queue count for east side
n = 10          // require 10 baboons to accumulate on the west side before interrupting
-------------------------------------------------------------------------------
mutex.signal()
	wait_east++;  // increment queue count
mutex.signal()

east.wait()
mutex.wait()  // check variables to see if baboon can get on rope
	if(count == 0 && block_west == 0)
		west.wait()  // block the west if not already blocked
	if(count > 0 && wait_west > n)
		block_east = 1; // wait_west interrupt is set, block east side 
                        // count must be greater than zero to ensure at least one baboon     
                        // to cross and avoid possible deadlock
	block_west = 0; // clear interrupt
	count++;        // increment count on rope / waiting to get on rope
	if(block_east == 0) east.signal() // allow east to continue, unless interrupt set
mutex.signal() // end check

rope.wait()  // use semaphore to allow more than 5 baboons to line up, 
             // only let 5 at a time through

## CS - baboon is crossing rope

mutex.wait()  	//once baboon is across rope, update variables
	count--; //decrement count of baboons on rope / waiting to get on rope
    wait_east--; //decrement queue count
	if(count == 0) // if the rope is empty
		west.signal()
	rope.signal()  // signal completion
mutex.signal()